How much sewer went un-captured if a spill was running at 6 gallons per minute for 27 minutes?

Get ready for the CWEA Collections Grade 2 Journey/Analyst Test. Study with multiple choice questions and detailed explanations to prepare effectively for the exam!

To determine how much sewer went un-captured during the spill, you can simply multiply the rate at which the sewer was spilling by the duration of the spill.

In this case, the spill was running at a rate of 6 gallons per minute for a duration of 27 minutes. Therefore, the calculation would be:

6 gallons/minute × 27 minutes = 162 gallons.

This shows that a total of 162 gallons of sewer went un-captured during the spill. The calculation process highlights the importance of understanding the relationship between rate, time, and total volume, which is key in managing and mitigating environmental incidents effectively.

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